174 9 Effective Elastic Constants of a Laminate EDU>>Qbar2 Qbar(Q,90) Qbar2 12.1584 3.0153 -0.0000 3.0153 155.7478 0.0000 -0.0000 0.0000 4.4000 EDU>>Qbar3 Qbar(Q,90) Qbar3 12.1584 3.0153 -0.0000 3.0153 155.7478 0.0000 -0.0000 0.0000 4.4000 EDU>>Qbar4 Qbar(Q,0) Qbar4 155.7478 3.0153 0 3.0153 12.1584 0 0 0 4.4000 Next,the distances zk(=1,2,3,4,5)are calculated as follows: EDU>>z1=-0.400 z1= -0.4000 EDU>>z2=-0.200 Z2= -0.2000 EDU>>z3 =0 z3= 0 EDU>>z4=0.200 z4= 0.2000174 9 Effective Elastic Constants of a Laminate EDU>> Qbar2 = Qbar(Q, 90) Qbar2 = 12.1584 3.0153 -0.0000 3.0153 155.7478 0.0000 -0.0000 0.0000 4.4000 EDU>> Qbar3 = Qbar(Q, 90) Qbar3 = 12.1584 3.0153 -0.0000 3.0153 155.7478 0.0000 -0.0000 0.0000 4.4000 EDU>> Qbar4 = Qbar(Q, 0) Qbar4 = 155.7478 3.0153 0 3.0153 12.1584 0 0 0 4.4000 Next, the distances zk(k = 1, 2, 3, 4, 5) are calculated as follows: EDU>> z1 = -0.400 z1 = -0.4000 EDU>> z2 = -0.200 z2 = -0.2000 EDU>> z3 = 0 z3 = 0 EDU>> z4 = 0.200 z4 = 0.2000