求1+1/2+1/3+……+1/100 #include <stdio. h> int main(void) int i, sum; int double sum sum =0; for(i=1;i<=100;i++) for(i=1;i<=100;i++ sum sum+ I sum=sum+1.0/i printf("sum =%din", sum) return 0 printf("sum =%f\n", sum)#include <stdio.h> int main(void) { int i, sum; sum = 0; for ( i = 1; i <= 100; i++ ) sum = sum + i; printf( “sum = %d\n”, sum); return 0; } 求 1+1/2+1/3+……+ 1/100 for(i=1; i<=100; i++) sum=sum+1.0/i; int i; double sum; printf( “sum = %f\n”, sum);