使用示例 bitSet<int>sl, S2, S3, S4, s5; bool index, equal for(intk=0;k<10;k++){/集合赋值 Sl. addMember(k) S2. addMember(k+7) s:④0,1,2,…,9},s2:{7,8,9,…,16} s3=sl+s2;/求s1与S2的并{0,1,…,16 s4=sls2;1求S1与S2的交{7,8,9} s5=s1-s2;/s1与S2的差{0,1,…,6}使用示例 bitSet<int> s1, s2, s3, s4, s5; bool index, equal; for (int k = 0; k < 10; k++) { //集合赋值 s1.addMember (k); s2.addMember(k+7); } //s1: {0, 1, 2, …, 9}, s2: {7, 8, 9, …, 16} s3 = s1+s2; //求s1与s2的并 {0, 1, …, 16} s4 = s1*s2; //求s1与s2的交 {7, 8, 9} s5 = s1-s2; //求s1与s2的差 {0, 1, …, 6} 10