int operator !O const i return curLen==0; j /判当前串*thi是否空串 String &operator=(String &ob); /将串ob赋给当前串*this String &operator +=(String &ob); /将串ob连接到当前串*th之后 char &operator [(int i ); /取当前串this的第i个字符 int Find( String& pat )constint operator ! ( ) const { return curLen == 0; } //判当前串*this是否空串 String &operator = (String &ob); //将串ob赋给当前串*this String &operator += (String &ob); //将串ob连接到当前串*this之后 char &operator [ ] ( int i ); //取当前串*this的第 i 个字符 int Find ( String& pat ) const; }