Transmission through a wall (4/5) The reflection coefficient at normal incidence for the air-medium interface is 1+Ve, The reflection coefficient for the second,medium-air interface is(see the expression of the reflection coefficients for normal incidence) Tno=ve-1 1+Ve, =-T0m Now if we consider the first interface we have 1En月Transmission through a wall (4/5) 0 1 1 r m r ε ε − Γ = + 0 0 1 1 r m m r ε ε − Γ = = −Γ + Srefl1 Sinc1 =  Erefl1 2  Ein1 2 = Γ0m 2 The reflection coefficient at normal incidence for the air-medium interface is The reflection coefficient for the second, medium-air interface is (see the expression of the reflection coefficients for normal incidence) Now if we consider the first interface we have