例7计算pH=10.0时EBT的(pMg) 已知:lgK(MgIm)=7.0 EBT:=1016B2=1017.9 an(田)=1+1010++10200+19=10,6 (pMgt=IgK(MgIn)=IgK(MgIn)-IgaIn(H) =7,0-1.6=545 例7 计算pH=10.0 时EBT的(pMg)t 已知： lgK(MgIn) = 7.0 EBT: 1＝1011.6 2＝1017.9 αIn(H) = 1 + 10-10.0+11.6 + 10-20.0+17.9 = 101.6 (pMg)t = lgK(MgIn) = lgK(MgIn) – lgαIn(H) = 7.0 – 1.6 = 5.4