y A to determine fc, AB is B resolved into Ac and CB X For: CB, F=o bcos. For: AC F=-obsin a AB→AB AC→A fe=F+F2=b(tx cos a-ox sin a)For : , ; For : , ② fc : x z y o b   C A B C A B to determine fc , is resolved into and AB → AB AB AC CB CB F1 =  xybcos AC F2 = − x bsin  AC → AC ( cos sin )  f c = F1 + F2 = b  xy  − x 