程序关键部分 for(=2;i<m;i++) if(m %/oi==0 break; if(i>=m) printf("%/od is a Prime muber n", m) else printf( %/od is not a Prime number \n", mi程序关键部分 for (i=2;i<m;i++) if(m%i==0) break; if(i>=m) printf("%d is a Prime muber＼n"，m); else printf("%d is not a Prime number＼n"，m); }