G=(X,Y) (a)S={x},T=Φ； (b)NS)={y2,y3},NS≠T,取y2∈N(S)-T (c)y2为M饱和点，y2X3∈M。此时，置S-SU{x3 T=TU{y2}。 (b)NS)={y2y3}≠T,取y3∈N(S)-T 110.8 1 0.6 0.4 0.2 0 x t 0 0.5 1 1.5 2 1 0.5 0 0.5 1 n 11 (a) S=｛x4｝,T=Φ; x1 x2 x3 x4 x5 y1 y2 y3 y4 y5 G=(X, Y) (b ) N(S)= ｛y2, y3｝,N(S)≠T, 取y2 ∈N(S)-T (c) y2为M饱和点，y2x3 ∈ M。此时，置S=S∪｛x3｝ T=T∪｛y2｝。 (b ) N(S)= ｛y2, y3｝ ≠T，取y3 ∈N(S)-T x4 y2 x3