The frequency response of the filter lH(i)=J1,90<1-4<180 0 otherwise as shown in the figure below: H(w) ∠H(ju) 200-100 100200 (a)Suppose s(t)=28(t-kr)and T 90 Provide a labeled sketch of Z Gw), the ourier transform o (b) Find y(t), assuming the s(t)and the value of T given in part(a) (c) The sampling function s(t)is changed to the form below, with T (1) (-1)(-1)(-1)(-1) Find y(t)� � � � � The frequency response of the filter is |H(j�)| = 1, 0, 90 < |�| < 180 otherwise �� �H(j�) = −200, as shown in the figure below: |H(j�)| �H(j�) 1 2 � 2 −� −180 −90 0 90 180 −200 −100 100 200 − � 2� (a) Suppose s(t) = �(t − kT) and T = . Provide a labeled sketch of Z(j�), the 90 k=−� Fourier transform of z(t). (b) Find y(t), assuming the s(t) and the value of T given in part (a). 2� (c) The sampling function s(t) is changed to the form below, with T = . 90 (1) (1) (1) (1) (1) t −T 2 −T −3T 2 −2T 0 T 2 T 3T 2 2T · · · · · · (−1) (−1) (−1) (−1) Find y(t). 2