A Typical Application Newton's law F=ma now gives mx"=Fs+FR; (2) that is d2x dx m +kx=0 (3) 4口y4元卡2月只0A Typical Application Newton’s law F = ma now gives mx 00 = FS +FR; (2) that is m d 2 x dt2 +c dx dt +kx = 0. (3) Thus we have a differential equation satisfied by the position function x(t) of the mass m. This homogeneous second-order linear equation governs the free vibrations of the mass