整距分布绕组的磁动 0,11,12 1,2,3 R=- 2sin C 2 R sin ga F,=2B=2Rsin ga =q内 2 2 qsin a-2 F,B G- F ,23 Fy f=(a)k1=4×X三kcos0.= 2W2 qN kI cose,cos ot 2 π π 4√2 fa =2(afe)ka= qN kaI cose cos wt 双层绕组整距分布绕组的磁动 势 k qN k I t qN i f qf k d s c d s c c q c d      cos cos 2 2 cos 2 4 ( ) 1 = 1 1 =  1 = 1 f qf k qN k I t q c d c d  s   cos cos 4 2 2( ) 1 = 1 1 = 1 双层绕组