The product yield coefficient can then be calculated, taking into account the relative numbers of carbons in the substrate and product. The molar yield coefficient is then product formed f'n substrate used a′ (mols product formed / mols substrate consumed) E-3.10 Where ns number of carbon atoms in the substrate molecule np=number of carbon atoms in the product molecule Determine the molar yield coefficient for exopolysaccharide production if 955 mols of glucose( C6H12 0 are required to produce one mol of Cs5 2 Ha.Os. Yp/s=(1x6)/(955x552)=0.011 type 2 For type 2 processes, the simple stoichiometry (E-3.9)does not apply Here, product formation is not necessarily proportional to substrate utilisation or biomass formation. In these cases, we need to consider a product formation step in addition to the growth reactions considered earlier, ie the formation (or utilistion) of both Nadh and atP relative to product formation d CHoY+H2O+(·Z)NAD d CHoW+ d(1-Z)cO+da(y-ZY )(ADH +H) Ep d(ADP+ P->Ep d(ATP+ H2O) E-3.12 Z= the fraction of carbon substrate used for convertion to prod Ep= the number of ATPs generated by product formation If the coefficient E in the product formation equation(E-3.12)was negative, would this indicate? The ATP is utilised rather than generated in connection with product formation. at does the coefficient d and the parameter denote in the product formation onCE-312)? The coefficient d denotes the extent to which the reaction occurs relative to the growth reaction. The parameter Yp denotes the degree of reductance of product44 Chapter 3 The product yield coefficient can then be calculated, taking into account the relative numbers of carbons in the substrate and product. The molar yield coefficient is then written as roductfod - f'n, - substrate used a'n, Yp/s = p (mols product formed/mols substrate consumed). Where: E - 3.10 ns = number of carbon atoms in the substrate molecule; np = number of carbon atoms in the product molecule. Determine the molar yield coefficient for exopolysaccharide production if 955 n mols of glucose (6H1206) are required to produce one mol of c65dk.Dfi.1. YP/. = (1 x 6) / (955 x 55.2) = 0.011 type 2 For type 2 processes, the simple stoichiometry (E - 3.9) does not apply. Here, product formation is not necessarily proportional to substrate utilisation or biomass formation. In these cases, we need to consider a product formation step in addition to the growth reactions considered earlier, ie the formation (or utilistion) of both NADH and ATP relative to product formation. d CHZoy + H20 + 2 (p - Z%)NAD+ > 1 E~~(ADP + Pi) > d (ATP + NO) Where: E - 3.11 E - 3.12 Z = the fraction of carbon substrate used for convertion to product; = the number of ATPs generated by product formation. If the coefficient ep in the product formation equation (E - 3.12) was negative, what n would this indicate? The ATP is utilised rather than generated in connection with product formation. What does the coefficient d and the parameter yp denote in the product formation equation (E - 3.12)? The coefficient d denotes the extent to which the reaction occurs relative to the growth reaction. The parameter rp denotes the degree of reductance of product