QUESTION 7 =w. (0.6×0.1+(04×0.20 =0.090.08 0.17 12+w2a2+2ww2r1.g1o √0.6×0,20)+(04×0,22)+(2×0.604×0.5×0 200.2 =√0.01440.0077440.01056 =√0.032704 =0.1808 QUESTION 8 k=∑Wxk (0.550.10+0450.1 =0.0550.0675 0.1225 ok,=vwia1+w202+2 w,w2r,g,O2 √0.53×026)+(0.45×0.28)+(2×0.550,450,3×0.200,28 √0.012+0.0158760008316 036292 =0.1905July 2003 QUESTION 7 ( ) ( ) = 0 .1 7 = 0 .0 9+ 0 .0 8 = 0 .6 0 .1 5+ 0 .4 0 .2 0 k = w k n j =1 p j j     ( ) ( ) ( ) 0 .1 8 0 8 = 0 .0 3 2 7 0 4 = 0 .0 1 4 4+ 0 .0 0 7 7 4 4+ 0 .0 1 0 5 6 = 0 .6 0 .2 0 + 0 .4 0 .2 2 + 2 0 .6 0 .4 0 .5 0 .2 0 0 .2 2 = w + w + 2 w w r 2 2 2 2 1 2 1 , 2 1 2 2 2 2 2 2 1 2 k 1 p =             QUESTION 8 ( ) ( ) = 0 .1 2 2 5 = 0 .0 5 5+ 0 .0 6 7 5 = 0 .5 5 0 .1 0+ 0 .4 5 0 .1 5 k = w k n j =1 p j j     ( ) ( ) ( ) 0 .1 9 0 5 = 0 .0 3 6 2 9 2 = 0 .0 1 2 1+ 0 .0 1 5 8 7 6+ 0 .0 0 8 3 1 6 = 0 .5 5 0 .2 0 + 0 .4 5 0 .2 8 + 2 0 .5 5 0 .4 5 0 .3 0 .2 0 0 .2 8 = w + w + 2 w w r 2 2 2 2 1 2 1 , 2 1 2 2 2 2 2 2 1 2 k 1 p =            