代入元件VCR,得IR+u+BR2+IR3-ls=0 R1=192,ls2=4v 1A tetr Pu=-Ll。I=-10W R,=2Q2 S 10V R2=392 Pu =um=4w5 A R R R u u I S S 1 1 2 3 1 2 = + + − = PuS1 = −uS1 I = −10W PuS2 = uS 2 I = 4W 0 1 2 2 3 1 代入元件VCR，得 IR + uS + IR + IR −uS = R1=1 uS2=4V I R3=3 uS1 =10V R2= 2 + - + -