32定点加减运算 ■例2 X=0.001010Y=0100011求[XY1补 解[灯]补=0.001010[Y补=0100011 则[XY补=[补+[Y补 =0.001010+0100011 =0.1011013.2 定点加减运算 ◼ 例2 X=0.001010 Y=-0.100011 求[X-Y]补 解 [X]补=0.001010 [-Y]补=0.100011 则 [X-Y]补 = [X]补+[-Y]补 = 0.001010 + 0.100011 = 0.101101