The rod Pendulum The torque about the rotation(z) axis is t=-mgd =-mgL2sine x-mgL210 for small 0 n this case I=。mL Soτ= la becomes L2 mg-0=mla XCM dL g a=-@ 0 where 2L Physics 121: Lecture 22, Pg 6Physics 121: Lecture 22, Pg 6 The Rod Pendulum... The torque about the rotation (z) axis is  = -mgd = -mg{L/2}sin  -mg{L/2} for small  In this case So  = Ia becomes  d L mg z L/2 xCM I = 1 3 2 mL  a 2 3 1 2 mL L − mg = a   2 = −  = 3 2 g L where d I