发“1”KQa,B)=l()emad pe=p(vsb)=f(v)dv=1-2(2r, b) r=a2/22信噪比 b=b/on归一化门限值 发“03 Pe=p(v>b)=fo(v)dv=e 总误码率P=P(1)P1+P(O)Pe2 若P(1)=P(0 p=[1-Q(2r,b)]+e24 发“1” 信噪比 归一化门限值 发“0” 总误码率 Pe=P(1)Pe1 + P(0)Pe2 若P(1)=P(0) ( ) ( ) 1 ( 2 , ) 1 0 1 b0 p p v b f v dv Q r b e =  =  = − 2 2 a / 2 n r =  n b0 = b / =  =  =  − b b e p p v b f v dv e / 2 2 0 2 0 ( ) ( ) / 2 0 2 0 2 1 [1 ( 2 , )] 2 1 b e p Q r b e − = − + =   − +   Q   tI t e dt (t )/ 2 0 2 2 ( , ) ( )