MT-1620 al.2002 dF 0→F=C d find C, via boundary condition @x=0, F=-P0=C1 Beam under its own weight Figure 17. 4 Representation of end-fixed column under its own weight Px =-mg dF dr+mg→F=mgx+C boundary condition: @X=, F=0 So:mg+C=0→C1=mg Paul A Lagace @2001 Unit 17-8MIT - 16.20 Fall, 2002 dF dx = 0 ⇒ F = C1 find C1 via boundary condition @x = 0, F = -Po = C1 ⇒ F = -Po • Beam under its own weight Figure 17.4 Representation of end-fixed column under its own weight px = -mg dF = + mg ⇒ F = mgx + C1 dx boundary condition: @ x = l, F = 0 So: mgl + C1 = 0 ⇒ C1 = -mgl Paul A. Lagace © 2001 Unit 17 - 8