(2) R=50 C=5uF L=0.4HRr=100 =220√2cos500V Find Ps and es 400 2=RL+joL=100+j200 oc 320+1240Z=R+2122=370+1240=4433 Z1+Z Z1+22 Z12 =Wz=0.5∠-33° Ⅰ=200∠3.9° Z1+Z 2 11=H1/Z1=0.5293.9°12=11/Z2=0.894∠-595° S=VI=923+j60VAS=Rr2=125 j100S2=1I2=80+160− + L • I R C s V • 1 • V L R 1 • I 2 • I (2) . 220 2 cos 500 0.4 100 50 5 s s s L Find P and Q tV L H R R C F = = = = =   400 100 200 1 1 2 j Z R j L j C Z = − j = − = L +  = +  320 240 1 2 1 2 j Z Z Z Z = + + = + =   + = + 370 240 441 33 1 2 1 2 j Z Z Z Z Z R = =  −  • • I V/ Z 0.5 33 =   + = • • 200 3.9 1 2 1 2 1 I Z Z Z Z V = =   = =  −  • • • • I 1 V1 / Z1 0.5 93.9 I 2 V1 / Z2 0.894 59.5 100 80 160 92.3 60 12.5 1 2 _ 1 1 2 _ 1 2 _ _ S V I j S V I j S V I j VA SR RI s s = = − = = + = = + = =  • •  • •  • •