Problem 1 (a) For this, we convert the part that is in cartesian form to polar form and proceed from tan 2 Plugging this into the expression we want to evaluate, we have √3+ 32e In graphical form, this can be represented as follows Figure 1.la: Magnitude and Phase plotProblem 1 (a) For this, we convert the part that is in cartesian form to polar form and proceed from there: � � 1 � � � 3 + j = tan−1 �3 = �/6 � �� 2 3 + j = � 3 + 12 | | = 2 � 3 + j = 2e�/6 . Plugging this into the expression we want to evaluate, we have: � 5 −j�/3 � 2ej�/6 �5 −j�/3 � 3 + j e = e j5�/6 −j�/3 = 25 e e· = 32ej�/2 In graphical form, this can be represented as follows: ≥e 32 ∞m Figure 1.1a: Magnitude and Phase plot 4