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1 Signal and System Energy over t1≤t≤t2: p()di (t )dt=x2(t)dt Total Energy Eoo=li x(t)dt Average Power: Po x(tdt 2T1 Signal and System Energy over t1 t  t2 :    = = 2 1 2 1 2 1 ( ) ( ) ( ) 2 2 t t t t t t p t dt v t dt x t dt Total Energy:  →  = 2 1 ( ) 2 lim t t T E x t dt Average Power: − →  = T T T x t dt T P ( ) 2 1 2 lim
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