数字电路习题答案(第一章) ()Y=A+B+CD F: Y=A(BCD+BCD+BCD+BCD+BCD+ BCD+BCD+BCD)+ B(ACD+ACD+ACD+ACD+ACD+ACD+ACD+ACD)+(AB+AB+AB+ ABCD ABCd+abcd+abcd+abcd+abcd+abC d+abcd+ ABCD+ ABCD+ABCD+ABCD+ABCD+ABCD(13) (4)Y=ABCD+ABCD+ ABCD+ABC D+ABCD+ ABoD+ABad+ABCD (5)Y=LMN+LMN+LMN +LM+LMN +LMN 1.12将下列各函数式化为最大项之积的形式 (1)Y=(A+B+C)(A+B+C)A+B+C) (2)Y=(A+B+C)(A+B+C)(A+B+C (3)Y=M0M3M4M6M2 (4)Y=M0·M4·M6·M9M12·M1 (5)y=M0M3M5 1.13用卡诺图化简法将下列函数化为最简与或形式 (1)Y=A+D (3)Y=1 (2)Y=AB +AC+BC+CD (4)Y=AB+AC+Be 5C00011110 110 Y=C+D+AB Y=AB+A (5)Y=B+C+D (6)Y=AB+AC+BC (7)Y=C (9)Y=BD+AD+ BC+ ACD (8)Y(A,B,C,D)=∑n(0,1,2,3,4,6,8.910,114) (10)Y(A,B,C)=∑(m,m4,m2) 11 00 100o1l 0100 1同 Y=B+cd+aD Y=ABC +ABC +ABC 1.14化简下列逻辑函数 (1Y=A+B+C+D (2)Y=CD+ACD (3)Y=AB+D+AC (4)Y=BC+BD (5Y=AB+ DE +CE+BDE +AD+ACDE 1.20将下列函数化为最简与或式 (1)Y=ACD+BCD+AD (2)Y=B+AD +Ac (3)y=A+B+C (4)Y=A+BD (5)Y=1 (6)Y=CD+BD+Ac数字电路 习题答案 （第一章） 2 (13) ( ) ( ) ( ) 3 ABCD ABCD ABCD ABCD ABCD ABCD ABCD ABCD ABCD ABCD ABCD ABCD ABCD B ACD ACD ACD ACD ACD ACD ACD ACD AB AB AB AB CD Y A BCD BCD BCD BCD BCD BCD BCD BCD Y A B CD + + + + + = + + + + + + + + + + + + + + + + + + = + + + + + + + + = + + 解： （ ） (4)Y = ABCD+ ABCD+ ABCD+ ABCD+ ABCD+ ABCD + ABCD + ABCD (5)Y = LM N + LMN + LMN + LMN + LMN + LMN 1.12 将下列各函数式化为最大项之积的形式 (1)Y = (A+ B +C )(A+ B +C)(A + B +C ) (2)Y = (A+ B +C)(A+ B +C)(A + B +C) (3)Y M0 M3 M4 M6 M7 = ⋅ ⋅ ⋅ ⋅ (4)Y M0 M 4 M6 M9 M12 M13 = ⋅ ⋅ ⋅ ⋅ ⋅ (5)Y M0 M3 M5 = ⋅ ⋅ 1.13 用卡诺图化简法将下列函数化为最简与或形式： (1)Y = A+ D (3)Y =1 (2)Y = AB + AC + BC + CD (4)Y = AB + AC + BC Y = C + D + AB Y = AB + AC (5)Y = B + C + D (6)Y = AB+ AC+BC (7)Y = C (9)Y = B D + AD + BC + ACD (8) ( , , , ) (0,1,2,3,4,6,8,9,10,11,14) Y A B C D = ∑m (10) ( , , ) ( , , ) Y A B C = ∑ m1 m4 m7 Y = B +CD + AD Y = ABC + ABC + ABC 1.14 化简下列逻辑函数 (1)Y = A + B + C + D (2)Y = CD + ACD (3)Y = AB + D + AC (4)Y = BC + BD (5)Y = AB + DE + CE + BDE + AD + ACDE 1.20 将下列函数化为最简与或式 (1)Y = ACD + BCD + AD (2)Y = B + AD + AC (3)Y = A + B +C (4)Y = A+ B D (5)Y =1 (6)Y = CD + B D + AC