例子(2) 。a[j]=c LD R1,c /R1=c LD R2,j /R2=j MUL R2,R2,8 /川R2=R2*8(8字节长元素) ST a(R2),R1 //contents(a contents(R2))=R1 。X=p LD R1,P /R1=P LDR2,0(R1) //R2 contents(0+contents(R1)) ST x,R2 /x=R2 8例子 (2) • a[j] = c – LD R1, c // R1 = c – LD R2, j // R2 = j – MUL R2, R2, 8 // R2 = R2 * 8 (8字节长元素) – ST a(R2), R1 // contents(a + contents(R2)) = R1 • x = *p – LD R1, p // R1 = p – LD R2, 0(R1) // R2 = contents(0 + contents(R1)) – ST x, R2 // x = R2 8 南大编译许畅