is by assumption a hurwitz matrix. On the other hand △(r,)-△(7,e)=o(e Combining this with △(r,e)=I+6(7)e+o(∈) yields △(r,e)=I+6(7)e+o() Since S()is a Hurwitz matrix, this implies that all eigenvalues of A(T, e) have absolute value strictly less than one for all sufficiently small E>05 is by assumption a Hurwitz matrix. On the other hand, �( ¯ �, �) − �(�, �) = o(�). Combining this with �( ¯ �, �) = I + �(� )� + o(�) yields �(�, �) = I + �(� )� + o(�). Since �(� ) is a Hurwitz matrix, this implies that all eigenvalues of �(�, �) have absolute value strictly less than one for all sufficiently small � > 0