MT-1620 al.2002 First the direct relation of e, to o 4 due to O4 only 4 This is engineering strain! and then due to OA only G 14 due to o only G Again, we use a reciprocity relation to get 41 m14 G E 14 m14 due to Oa on E We do the same for Case 5 of only os applied, and Case 6 of only os applied to Paul A Lagace @2001 Unit 5-p. 12MIT - 16.20 Fall, 2002 First the direct relation of ε4 to σ4: G4 = σ4 due to σ4 only ε4 This is engineering strain! and then: η41 = − ε1 due to σ4 only ε4 σ4 = − ⇒ G4 ε1 η41 ⇒ S14 = − η41 due to σ4 only G4 Again, we use a reciprocity relation to get: η41 η14 = G4 E1 ⇒ S14 = − η14 due to σ4 only E1 We do the same for Case 5 of only σ5 applied, and Case 6 of only σ6 applied to Paul A. Lagace © 2001 Unit 5 - p. 12