S2=-(0.11113057)A2=6.18 x3=x2+2S2=(2013210058) lVf(x)|0.006<E f(x3)F5×10 x3已满足要求,它比用DFP算法迭代7步的结果(2115,1058)还好 190190 (0.11113,0.05570) 2 6.18 2 = −  = T S T x x S (2.0132,1.0058) 2 2 3 2 = +  = ||  ( ) ||= 0.006   3 f x 3 6 | ( ) | 5 10− f x =  3 x 已满足要求，它比用 DFP 算法迭代 7 步的结果 (2.115,1.058) 还好