000 12 In b 0bbb∶b 000….1an1an2 C=(0,1,1,1,0,0 显然问题(Ⅱ)有一现成的可行基 01 B 00:0 称为人造基) 00. 0 . 0 0 0 1 0 0 1 0 0 1 0 0 1 0 0 0 3 2 1 1 2 2 1 2 2 2 1 1 1 2 1 1 2 = − − − = m m m m n n n n b b b b a a a a a a a a a c c c A b C=(0,1,1, ···,1,0,0, ···, 0) (称为人造基) 0 0 0 1 0 1 0 0 1 0 0 0 = B 显然,问题(Ⅱ)有一现成的可行基