NH 0.1 NH E 3 =0.03=10-1mo|.L 05 NH3(H) 100 或 109;4×0.1 NH,|= 3」--0 =0.03mo|·L 3)1090+109.4 Ln(NH3 1+NH31B,+[NH31B2+ B3+[ 4B4 =10321ga Zn(NH3) 3.28 ( ) ( ) 3 -1.5 -1 3 0.5 NH H 3 NH 0.1 NH = = = = 10 mol 0.03 1 : 0 L c      或  ( ) 3. = 3.2 H3 2 Zn N =10 lg Zn(NH3)= 1+[NH3 ]1+[NH3 ] 2  2+[NH3 ] 3  3+[NH3 ] 4  4 ( ) -1 -9.4 3 0 3 -9.0 -9.4 10 0.1 NH = NH = = 0.03 mol L 10 +10 x c       