100 50 Me=-(50×5)=-250'-k (from statics) Mab=2EK(0。-3)-22.2 20 Ma=2EK(20。-3)+44.4 M=2E·3K(20b+0)-288 汤 n 8 20 5 Mb=2E·3K(20e+6b)+192 Mcd=2EK(20。-3ψ) Equilibrium Equations Mk=2EK(0e-3ψ) At joint b: Msa Moc =0 250h At joint c: M+M-250=0 学院 17 Columns ab and cd: 5 204 10 一H Mab M from consideration of the entire structure, H。+Ha=20 .'.Mab Mpe Mca+Mac =-200 Substitution of moment equations into the equilibrium equations yields 6 -61EK06l [243.6 6 16 EKO。 58.0 -6 24 EK业 222.2 18