设输入的抑制载波双边带信号为m()coso WU V=m(t)cos@t cos(at+0) m(t)[ 6+cos(20 t+0)] V4=m(t)cosotsin(ot+0) m(t)[ e+sin(2ot +01 经低通后的输出分别为: V=m(t)cos0 V6 m(t)sin e 210 设 输入的抑制载波双边带信号为 则 m t t c ( )cos ( )cos cos( ) V3 = m t c t c t + ( )[cos cos(2 )] 2 1 = m t + c t + ( )cos sin( ) V4 = m t c t c t + ( )[sin sin(2 )] 2 1 = m t + c t + 经低通后的输出分别为: ( )cos 2 1 5 V = m t ( )sin 2 1 6 V = m t