正在加载图片...
例 (4个结点,6条支路) 1.KCL:(独立方程数n-1=3) ③ node 1:-i+i+i=0 node 2:-i2-i3 +i=0 n-1=3 node3:-i4-6+i5=0 <1> 2.VCR:(独立方程数b=6) u=iR-us1 u2=iR2 u3-igR3 b-6 u4=iR4 us=(is+is5)Rs ug=i6R6 3.KVL:(独立方程数b-n+1=3)选自然网孔 以(2,3,4)为树支 loop1:iR-i3R3=0 5 loop 2:Rs iRs0s+iss)Rs=0 l0op3:86u4P-9呱2=司 b-n+1=-3 整理得: iR+iR2-i3R3=UsI i3R3+iR4+isRs=issRs <2> i6R6i4R4-i2R2=0 最终,方程组由<1><2>组成。ֻ ˄4њ㔃⛩ˈ6ᶑ᭟䐟˅ 1.KCL˖(⤜・ᯩ〻ᮠn-1=3) node 1: -i1+ i2 + i6 =0 node 2: -i2 - i3 + i4 =0 node 3: -i4 - i6 + i5 =0 n-1=3 2.VCR˖(⤜・ᯩ〻ᮠb=6) u1= i1R1 - us1 b=6 i1R1 - us1+ i2R2 - i loop1: 3R3 =0 loop 2: loop 3: i3R3 + i4R4 + (i5+is5)R5 =0 i6R6 - i4R4 - i2R2 =0 b-n+1=3 ᮤ⨶ᗇ˖ i1R1+ i2R2 - i3R3 = us1 i3R3 + i4R4 + i5R5 = is5R5 i6R6 - i4R4 - i2R2 =0 ᴰ㓸ˈᯩ〻㓴⭡<1> <2>㓴ᡀDŽ <1> <2> u2= i2R2 u3= i3R3 u4= i4R4 u5= (i5+is5)R5 u6= i6R6 u1+ u2 - u3 =0 u3 + u4 + u5 =0 u6 - u4 - u2 =0 3.KVL˖(⤜・ᯩ〻ᮠ b-n+1=3) 䘹㠚❦㖁ᆄ ԕ(2,3,4)Ѫṁ᭟
<<向上翻页向下翻页>>
©2008-现在 cucdc.com 高等教育资讯网 版权所有