2012 Semifinal Exam Part A 5 SO 92 v=Vg+9=反 Then Y=1/V1-1/2=2 It isn't much work to find the kinetic energy, K=y-1)Mc2=(W2-1)Mc2. c.This is a velocity addition problem,so US +US w=1+s212 or,using the numbers from the first part of the problem, V1-4a2 U= 1-2a2 Copyright C2012 American Association of Physics Teachers2012 Semifinal Exam Part A 5 so v = c r 9 2 9 2 + 92 = c √ 2 Then γ = 1/ p 1 − 1/2 = √ 2 It isn’t much work to find the kinetic energy, K = (γ − 1)M c2 = (√ 2 − 1)M c2 . c. This is a velocity addition problem, so v = vS + vS 1 + vS 2/c2 or, using the numbers from the first part of the problem, v = c √ 1 − 4α2 1 − 2α2 Copyright c 2012 American Association of Physics Teachers