例3求imxx0 x→0+ im xinx 解:原式=lim rinx 0 x→>0+ lim Inx x->0+ Im c→>0+ 2例3 求 x x x → + 0 lim 解: 原式= x x x e ln 0 lim → + 0 0 x x x e lim ln 0 → + = x x x e 1 ln lim 0 → + = 2 0 1 1 lim x x x e − → + = =e 0 =1