例 已知Z=10+j6.282,Z2=20-j31.92,Z3=15+j15.72。 求Zab ao☐ bo 解 Z,Z2_(10+j6.28)20-j31.9) 7三Z+210+i628+20-3) =11.81∠32.13°×37.65∠-57.61° 39.45∠-40.5° =10.89+j2.862 ∴.Zb=Z3+Z=15+j15.7+10.89+j2.86 =25.89+j18.56=31.9∠35.6°210 j6.28 20 j31.9 (10 j6.28)(20 j31.9) 1 2 1 2       Z Z Z Z Z ֻ ᐢ⸕ Z1=10+j6.28:, Z2=20-j31.9 :, Z3=15+j15.7 : DŽ Z2 Z1 Z3 a b ≲ ZabDŽ 25.89 j18.56 31.9 35.6 ȍ 15 j15.7 10.89 j2.86 ab 3  ‘ q ? Z Z  Z    䀓 ‘  q ‘ q u ‘  q 39.45 40.5 11.81 32.13 37.65 57.61 10.89  j2.86: