偏移理想条件下的后果滑差 并列时的电气状态: 0fG≠fx 断路器QF两侧的电压差为脉动 电压: (ox t+2) lagt+p1) =Umg sin(ogt+u)-Umx sin (oxt+2) 1=2=0 s=LOmG Sing- O。+O t cos scos动c+0s U 脉动电压的幅值 20212/11 North China Electric Power University page202021/2/11 North China Electric Power University page20 偏移理想条件下的后果----滑差 U X UG US G X + j ( ) + 2 t X ( ) +1 t G e 并列时的电气状态: UG = UX e = 0 G X f f 断路器QF两侧的电压差为脉动 电压: ( ) ( ) 1 2 uS = UmG sin G t + −UmX sin X t + 1 =2 = 0 + = + − = U t u U t t G X S G X G X S m G 2 cos 2 cos 2 2 sin 脉动电压的幅值