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Partial Molar Quantities (3) S.J.T.U. Phase Transformation and Applications dv V adna +V Bdng Intergrating along a special path in which the ratio of n and ne remains constant. v=Vana+VBnB nA一+VBnA+nB V一=VA4+nB nB na+nB V=VaxA+VBXB dy=V adx+V BdxB where xA and xB are the mole fractions of A and B in the solution,and V its molar volume. SJTU Thermodynamics of Materials Spring2006©X.J.Jin Lecture 12 Solution IPhase Transformation and Applications S. J. T. U. SJTU Thermodynamics of Materials Spring 2006 © X. J. Jin Lecture 12 Solution I Partial Molar Quantities (3) A A += BnVnVV B BA B B BA A A BA nn n V nn n V nn V + + + = + A A B B += xVxVV A A B B += dxVdxVVd Intergrating along a special path in which the ratio of nA and nB remains constant. A A += BdnVdnVdV B where xA and xB are the mole fractions of A and B in the solution, and V its molar volume
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