腔内介质的微扰 可知 V·(E0xB)=H.V×E-EnV× J(o0fB·H-1OE·E(35-8) V·(E0xH)=H0VxE0-E.V×H0 (35-9) H+jo Eo 把上面结果合在一起考虑为 V(E0xH)+V.(ExH)=(10-0)HD·H+(0n-0)En·E (35-10)可知 (35-8) = − = − ( ) * * * * * E H H E E H j H H j E E 0 0 0 0 0 0 0 = − = − + ( ) * * * * * * * E H H E E H j H H j E E 0 0 0 0 0 0 0 0 0 (35-9) 把上面结果合在一起考虑为 ( ) + ( ) = ( − ) + ( − ) * * * * E0 H E H0 j 0 0 H0 H j 0 0 E0 E (35-10) 一、腔内介质的微扰