西安毛子科技大学XIDIANUNIVERSITY练习： 求 A(a) 的不变因子000an00元-1...an-10002a000a+a答案:d,(a) =..= dn+1(a) =1,dn(a)=A(a))=an +an-ia +..+a,an-I + a".练习：求 A( )  的不变因子 ( ) 1 2 1 0 0 0 1 0 0 0 0 0 0 0 0 1 n n a a A a a      −     − =       − +   答案: ( ) ( ) 1 1 1 , n d d   = = = + ( ) ( ) 1 1 1 . n n n n n d A a a a      − = = + + + + −