矩阵的逆与线性方程组的解 ax1+a12x2+…+arxa=b】 a2ix1+a2x2+…+a2ra=b anix1十a2x2十…+AnnXn=bm 一一一一一一一 all a12 din b 021 a22 a2n X2 ani an2 ann Xn or,equivalently,letting A =(a),x=(xi),and b =(b:).as Ax =b. If A is nonsingular,it possesses an inverse A,and =Ab矩阵的逆与线性方程组的解