lc(0+)=lCc(0_),i(04)=iz(0) 因为, uc(t)=uc(to)+li(s)d5 (0=(n)+.505 =0时换路 uc(f)=(0 (sds t i(t)=i(0_)+ u(s)ds 计算t=04时的值,有 (04)=uc(0)+idt LtU+ 十 udt(0 ) (0 ), (0 ) (0 ) C + = C − L + = L − u u i i 因为，     ( )d 1 ( ) ( ) ( )d 1 ( ) ( ) 0 0 0 0   = + = + t t L L t t C C u L i t i t i C u t u t     ( )d 1 ( ) (0 ) ( )d 1 ( ) (0 )   + − + − = + = + − − t t L L t t C C u L i t i i C u t u t = 0 时换路 计算t = 0+ 时的值，有 u t L i i i t C u u t t L L t t C C d 1 (0 ) (0 ) d 1 (0 ) (0 )   + − + − = + = + + − + −