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IS(0)T(p)1=bS(0)T(p) 88 d)ibd T()方 T()=Aeiboin (4.18) 依单值条件有 T(2=T( (4.19) Aebo1heb2π/h=Aebp1h eib2π1h =1 (4.20)[ ( ) ()] ( ) ()  i S T = bS T   −     d ib T dT  = ( ) ( ) /  ( )   ib T = Ae (4.18) 依单值条件有 T(+2) = T() (4.19) i b /  i b  /  i b /  Ae e = Ae 2 1 2 = ib  /  e (4.20)
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