0.4 g 0.512 0.20 1+3.28×0.3×√04 anr=0.63×0.1=0063(m) 0.512×2 04 0.708 1+3.28×0.4×√0.4 SOZ =0.20 0.20×0.1=0020(moL)0.20 1 3.28 0.3 0.4 0.4 lg 0.512 12 Cl = − + × × γ − = − × 0.63 Cl γ − = 0.63 0.1 0.063 Cl a − = × = (mol/L) 0.708 1 3.28 0.4 0.4 0.4 lg 0.512 22 so24 = − + × × γ − = − × 2 0.20 SO4 γ − = 2 0.20 0.1 0.020 SO4 a − = × = (mol/L)