10 0 0 x 0 (5) x"十a1x+…十a,1x+a a2+al 证明 b b-a (1)左边= 2a b-a 26-2a 0 b-a2 b2 b-a 26-2 b+ (a-b)3=右边 (2)左边按第一列叩+bzaz+bx +bz az+ b 分开az+bxax+例+bzaz+bxax+b z ax+by ay+b x ax+by ay+b +bz z az+b 分别再分 a'y az+ bx x+0+0+bz x ax+by x + by y ayt 分别再分 x y z y z x z x+bz x y yz +b 1)2=右边 a2a2+(2a+1)(a+2)(a+3) (3)左边 b2b2+(2b+1)(b+2)2(b+3) +(2c+1)(c+2)(Cc+3) d2+(2d+1)(d+2)2(d+3)5 (5) 1 2 2 1 0 0 0 1 0 1 0 0 1 0 0 0 a a a a x a x x xn n n +− − − − −         n n n n = x + a x + + a − x + a − 1 1 1  . 证明 (1) 1 0 0 2 2 2 2 2 2 2 3 1 2 1 a b a b a a ab a b a c c c c − − − − −− 左边 = b a b a ab a b a 2 2 ( 1 ) 2 2 2 3 1 − − − − = − + 1 2 ( )( ) a b a b a b a + = − − = ( a − b ) 3 = 右边 (2) z ax by ay bz y az bx ax by x ay bz az bx a + + + + + + 分开 按第一列 左边 x ax by ay bz z az bx ax by y ay bz az bx b + + + + + + + + + + +++ 0 0 2 z ax by y y az bx x x ay bz z a 分别再分 x y ay bz z x ax by y z az bx b +++ x y z z x y y z x b z x y y z x x y z a 3 3 + 分别再分 = 3 + 3 (−1)2 = 右边 z x y y z x x y z b z x y y z x x y z a (3) 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 (2 1) ( 2) ( 3) (2 1) ( 2) ( 3) (2 1) ( 2) ( 3) (2 1) ( 2) ( 3) + + + + + + + + + + + + + + + + = d d d d d c c c c c b b b b b a a a a a 左边