由不确定关系,求一维谐振子基态能量 解,能量.E=P1 +mO2x2,设△x=a,Ap=h/2a 2m2 束缚态,x=p=0,Ax2=(x-x)2=x2=a2 p2=(p-p)2=p2=h2/4a2,代入E式 h dE E +-m0 =0→a 8ma22 、E=h0/2 2由不确定关系,求一维谐振子基态能量 , / 2 2 , 0 2 1 8 ( ) / 4 0, ( ) , , / 2 2 1 2 , 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 = + = = = = − = = = = = − = = = + = = E m a da dE m a m a E p p p p a E x p x x x x a m x x a p a m p E ,代入 式 束缚态, 解,能量 设