Source transformation -10 F07 2+4 05A 4-2 2-|1V 4-j2+2-n1 4-j2-八10+2+/0.6+/0.3 1=4-j2-I(4-j2)=1-j2 V2=I(2+j4)-(2-j1)=-2+j4Source transformation: 0.6 0.3 4 2 10 2 4 4 2 2 1 j j j j j j I = + − − + + − + − = • V1 = 4 − j2 − I(4 − j2) = 1− j2V • • V 2 = I(2 + j4) − (2 − j1) = −2 + j4V • • 1 • V 2 • V A  0 1