Thevenin’ s theoren: e=1×(4j2)-j0.5(2+j4) 2+14 6-j3 0.5A ztn=(4-j2)+(2+j4)=6+j2 10241 6-j3 4-12 2+4 0.6+j0.3 05A 6+j2-10 -110 1=(4j2)1-(0.6+j0.3=1-j2 6-3v 6+2 2=(2+j4(0.6+j0.3)+j0.5]=-2+j4Thevenin’s theorem: j V V o c j j j 6 3 1 (4 2) 0.5(2 4) = − =  − − + • Zt h = (4− j2)+ (2+ j4) = 6+ j2 0.6 0.3 6 2 10 6 3 j j j j I = + + − − = • V1 = (4 − j2)[1− (0.6 + j0.3)] = 1− j2V • V 2 = (2 + j4)[(0.6 + j0.3) + j0.5] = −2 + j4V •