E(t) 0) (a) (b) A uc(0) =20 uc(0_) sC SC 1 R+- S 1A-uc(0_),uc(0_ 2=A A uc(0_) S SCR+1 S S s+1/RC s+1/RC 3)求反变换 a 99 s RC u s RC A s A s u sCR A u s s u sC R s u s A s sC u sC I s U s C C C C C C 1/ (0 ) 1/ (0 ) 1 1 (0 ) (0 ) 1 (0 ) ( ) (0 ) 1 ( ) + + + + = − + − = + + − = + = − − − − − − (1 ) (0 ) ( ) ( ) (0 ) ( ) 3) / / / / A e u e t u t A Ae u e t t R C C t R C t R C C t R C C − − − − − − = − + = − + 求反变换