Mesh analysis: 3 500LF ms1:31+j4(1-12)=10 )102cos103nr3寸uH 2i,msh2:j4(2-1)-j212+2l1=0 3+j4)1-412=10 2-j4)l1+j2l2=0 (10∠01)3 21 14+J 8 1.24∠297°A 20+j30 =277∠56.3°AMesh analysis: 1: 3 1 + 4( 1 − 2 ) = 10 • • • mash I j I I 2 : 4( 2 − 1 ) − 2 2 + 2 1 = 0 • • • • mash j I I j I I     − + = + − = • • • • (2 4) 2 0 (3 4) 4 10 1 2 1 2 j I j I j I j I or . . A j I  1 24 29 7 13 14 8 1 =  + = • A j I  2.77 56.3 13 20 30 2 =  + = • 1 • I 2 • I