《电路》（英文版）8-1 Nodal, mesh and loop analysis Nodal analysis

88-1 Nodal, mesh and loop analysis Nodal analysis: (2+j2)V1-j12=10 j1+(1-j1)2=)5 (1+0 5 10 15 -0.5A 10-j Re∫ 51-川5-谁10 2+2-j 5 node 1 十 j10一j5j10 1-ⅳ2=2.24∠-63.4°V V2 node 2 5 J0× 510 (-10.5)v2=-2+j4=447116°V

§8-1 Nodal,mesh and loop analysis Nodal analysis: 1 5 10 5 10 1: 1 1 1 2 1 2 = − + − − + − + • • • • • • j V V j V V j V V node ( j . ) V j V j V V j V V node : 0 5 5 10 5 10 2 2 1 2 1 2 2 + + = − − − + − − • • • • • •     − + − = + − = • • • • (1 1) 5 (2 2) 10 1 2 1 2 jV j V j j V jV or j V j j j j j j j j V  1 2 2.24 63.4 5 5 10 1 1 2 2 5 1 1 10 1 = − =  − − = − − + − − − = • V j V  2 = −2 + 4 = 4.47116.6 •

Mesh analysis: 3 500LF ms1:31+j4(1-12)=10 )102cos103nr3寸uH 2i,msh2:j4(2-1)-j212+2l1=0 3+j4)1-412=10 2-j4)l1+j2l2=0 (10∠01)3 21 14+J 8 1.24∠297°A 20+j30 =277∠56.3°A

Mesh analysis: 1: 3 1 + 4( 1 − 2 ) = 10 • • • mash I j I I 2 : 4( 2 − 1 ) − 2 2 + 2 1 = 0 • • • • mash j I I j I I     − + = + − = • • • • (2 4) 2 0 (3 4) 4 10 1 2 1 2 j I j I j I j I or . . A j I  1 24 29 7 13 14 8 1 =  + = • A j I  2.77 56.3 13 20 30 2 =  + = • 1 • I 2 • I

oop analvsis 31+(-2)(I1+l2)+21=10 (-j2)(1+I2)+21+j4l2=0 0∠0q 21 (5-j2)1-j212=10 (2-j2)1+j2l2=0 14+i8 =1.24∠297°4 13 1,=2-j2 6+j22 j2 13 14+J 86 2 +12220+30 2.77∠56.3°A 13 13 13

Loop analysis: 3 1 + (− 2)( 1 + 2 ) + 2 1 = 10 • • • • I j I I I (− 2)( 1 + 2 ) + 2 1 + 4 2 = 0 • • • • j I I I j I     − + = − − = • • • • (2 2) 2 0 (5 2) 2 10 1 2 1 2 j I j I j I j I or . . A j I  1 24 29 7 13 14 8 1 =  + = • 13 6 22 2 2 2 2 1 j I j j I + = − = − • • . . A j j j I I  2 77 56 3 13 20 30 13 6 22 13 14 8 1 2 =  + = + + + + = • • 2 • I 1 • I